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Proof:
|
ρ
N(M/M/1) = ------- ..... (click here)
1 - ρ
|
T = N / λ (Little's formula in another form)
|
Therefore, the average service time of the M/M/1 queue is
N
T = ---
λ
1 ρ
= --- * -------
λ 1 - ρ
1 λ/μ
= --- * -------
λ 1 - ρ
1 1
= --- * ------- ..... (3)
μ 1 - ρ
|