|
Proof:
|
ρ N(M/M/1) = ------- ..... (click here) 1 - ρ |
T = N / λ (Little's formula in another form) |
Therefore, the average service time of the M/M/1 queue is
N T = --- λ 1 ρ = --- * ------- λ 1 - ρ 1 λ/μ = --- * ------- λ 1 - ρ 1 1 = --- * ------- ..... (3) μ 1 - ρ |