|
in terms of p0 (10 pts)
Each printer has a exponentially distributed operational lifetime with an average life time of 1/λ. This will result in a Poission process with rate λ. Printer failures are independent; so the printer "failure rate" when k printers are operational is equal to k × λ
The office has a printer repait shop with one printer repair technician. The technician can repair a printer in an average repair time of 1/μ. This will result in a Poission process with rate μ.
|