Proof: by showing the following 3 claims:
Proof:
(Sender can timeout on an outstanding frame and re-transmit)
the sender will keep sending the data frame
Therefore:
the receiver will have the opportunity to receive the data frame x
I.e.: frame x must not be inside the send window
In other words:
And this situation is impossible because we have shown that:
See: click here
the receiver can receive duplicate frame x
also slide the receiver window pass the value x !!!
Retransmission of data frame x are discard !!!
(Namely: x, x+1, x+2, ....)