I reformulated them under one common theme:
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(You have seen these types of queries before !!! It will be boring to repeat them)
I put them in the webpage below for your convenience.
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Solution:
ResearchDept = σdname='Research' ( Department ) ResearchProjs = Project ⋈dnum=dnumber ResearchDept EmpResProjs = πessn ( Works_on ⋈pno=pnumber ResearchProjs ) Answer = πfname, lname ( Employee ⋈ssn=essn EmpResProjs ) |
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Solution:
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Solution:
Hint:
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Solution procedure:
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Solution:
Hint:
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Solution procedure:
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Solution: